5x-(x/2)^2-x=0

Solution for 5x-(x/2)^2-x=0 equation:

5x-(x/2)^2-x=0

We add all the numbers together, and all the variables

5x-(+x/2)^2-x=0

We add all the numbers together, and all the variables

4x-(+x/2)^2=0

We multiply all the terms by the denominator


4x*2)^2-(+x=0

We add all the numbers together, and all the variables

x+4x*2)^2-(=0

Wy multiply elements

8x^2+x=0

a = 8; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·8·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*8}=\frac{-2}{16}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*8}=\frac{0}{16}
=0
$